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Triangle Proportionality

Sides divided by a line parallel to the third side of a triangle.

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Triangle Proportionality

Triangle Proportionality 

Think about a midsegment of a triangle. A midsegment is parallel to one side of a triangle and divides the other two sides into congruent halves. The midsegment divides those two sides proportionally.

Investigation: Triangle Proportionality

Tools Needed: pencil, paper, ruler

  1. Draw \begin{align*}\triangle ABC\end{align*}. Label the vertices.
  2. Draw \begin{align*}\overline{XY}\end{align*} so that \begin{align*}X\end{align*} is on \begin{align*}\overline{AB}\end{align*} and \begin{align*}Y\end{align*} is on \begin{align*}\overline{BC}\end{align*}. \begin{align*}X\end{align*} and \begin{align*}Y\end{align*} can be anywhere on these sides.
  3. Is \begin{align*}\triangle XBY \sim \triangle ABC\end{align*}? Why or why not? Measure \begin{align*}AX, XB, BY,\end{align*} and \begin{align*}YC\end{align*}. Then set up the ratios \begin{align*}\frac{AX}{XB}\end{align*} and \begin{align*}\frac{YC}{YB}\end{align*}. Are they equal?
  4. Draw a second triangle, \begin{align*}\triangle DEF\end{align*}. Label the vertices.
  5. Draw \begin{align*}\overline{XY}\end{align*} so that \begin{align*}X\end{align*} is on \begin{align*}\overline{DE}\end{align*} and \begin{align*}Y\end{align*} is on \begin{align*}\overline{EF}\end{align*} AND \begin{align*}\overline{XY} \ || \ \overline{DF}\end{align*}.
  6. Is \begin{align*}\triangle XEY \sim \triangle DEF\end{align*}? Why or why not? Measure \begin{align*}DX, XE, EY,\end{align*} and \begin{align*}YF\end{align*}. Then set up the ratios \begin{align*}\frac{DX}{XE}\end{align*} and \begin{align*}\frac{FY}{YE}\end{align*}. Are they equal?

From this investigation, it is clear that if the line segments are parallel, then \begin{align*}\overline{XY}\end{align*} divides the sides proportionally.

 

Triangle Proportionality Theorem: If a line parallel to one side of a triangle intersects the other two sides, then it divides those sides proportionally.

Triangle Proportionality Theorem Converse: If a line divides two sides of a triangle proportionally, then it is parallel to the third side.

Proof of the Triangle Proportionality Theorem:

Given: \begin{align*}\triangle ABC\end{align*} with \begin{align*}\overline{DE} \ || \ \overline{AC}\end{align*}

Prove: \begin{align*}\frac{AD}{DB}=\frac{CE}{EB}\end{align*}

Statement Reason
1. \begin{align*}\overline{DE} \ || \ \overline{AC}\end{align*} Given
2. \begin{align*}\angle 1 \cong \angle 2, \angle 3 \cong \angle 4\end{align*} Corresponding Angles Postulate
3. \begin{align*}\triangle ABC \sim \triangle DBE\end{align*} AA Similarity Postulate
4. \begin{align*}AD + DB = AB, EC + EB = BC\end{align*} Segment Addition Postulate
5. \begin{align*}\frac{AB}{BD}=\frac{BC}{BE}\end{align*} Corresponding sides in similar triangles are proportional
6. \begin{align*}\frac{AD+DB}{BD}=\frac{EC+EB}{BE}\end{align*} Substitution PoE
7. \begin{align*}\frac{AD}{BD}+\frac{DB}{DB}=\frac{EC}{BE}+\frac{BE}{BE}\end{align*} Separate the fractions
8. \begin{align*}\frac{AD}{BD}+1=\frac{EC}{BE}+1\end{align*} Substitution PoE (something over itself always equals 1)
9. \begin{align*}\frac{AD}{BD}=\frac{EC}{BE}\end{align*} Subtraction PoE

 

Determining Ratios 

A triangle with its midsegment is drawn below. What is the ratio that the midsegment divides the sides into?

The midsegment’s endpoints are the midpoints of the two sides it connects. The midpoints split the sides evenly. Therefore, the ratio would be \begin{align*}a:a\end{align*} or \begin{align*}b:b\end{align*}. Both of these reduce to 1:1.

Solving for Unknown Lengths 

In the diagram below, \begin{align*}\overline{EB} \ || \ \overline{CD}\end{align*}. Find \begin{align*}BC\end{align*}.

Use the Triangle Proportionality Theorem.

\begin{align*}\frac{10}{15} = \frac{BC}{12} \longrightarrow 15(BC) &= 120\\ BC &= 8\end{align*}

 

 

Determining if Two Lines are Parallel 

Is \begin{align*}\overline{DE} \ || \ \overline{CB}\end{align*}?

Use the Triangle Proportionality Converse. If the ratios are equal, then the lines are parallel.

\begin{align*}\frac{6}{18}=\frac{1}{3}\end{align*} and \begin{align*}\frac{8}{24}=\frac{1}{3}\end{align*}

Because the ratios are equal, \begin{align*}\overline{DE} \ || \ \overline{CB}\end{align*}.

 

Examples

The following Examples use the diagram below. \begin{align*}\overline{DB} \| \overline{FE}\end{align*}.

Example 1

Name the similar triangles. Write the similarity statement.

\begin{align*}\triangle DBC \sim \triangle FEC\end{align*}

Example 2

\begin{align*}\frac{BE}{EC} = \frac{?}{FC}\end{align*}

DF

Example 3

\begin{align*}\frac{EC}{CB} = \frac{CF}{?}\end{align*}

DC

Example 4

\begin{align*}\frac{DB}{?} = \frac{BC}{EC}\end{align*}

FE

Example 5

\begin{align*}\frac{FC+?}{FC} = \frac{?}{FE}\end{align*}

DF; DB

Review 

Use the diagram to answer questions 1-7. \begin{align*}\overline{AB} \ || \ \overline{DE}\end{align*}.

  1. Find \begin{align*}BD\end{align*}.
  2. Find \begin{align*}DC\end{align*}.
  3. Find \begin{align*}DE\end{align*}.
  4. Find \begin{align*}AC\end{align*}.
  5. What is \begin{align*}BD:DC\end{align*}?
  6. What is \begin{align*}DC:BC\end{align*}?
  7. We know that \begin{align*}\frac{BD}{DC}=\frac{AE}{EC}\end{align*} and \begin{align*}\frac{BA}{DE}=\frac{BC}{DC}\end{align*}. Why is \begin{align*}\frac{BA}{DE} \neq \frac{BD}{DC}\end{align*}?

Use the given lengths to determine if \begin{align*}\overline{AB} \ || \ \overline{DE}\end{align*}.

Find the unknown length.

  1. What is the ratio that the midsegment divides the sides into?

Review (Answers)

To view the Review answers, open this PDF file and look for section 7.8. 

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Vocabulary

Congruent

Congruent figures are identical in size, shape and measure.

midsegment

A midsegment connects the midpoints of two sides of a triangle or the non-parallel sides of a trapezoid.

Parallel

Two or more lines are parallel when they lie in the same plane and never intersect. These lines will always have the same slope.

Proportion

A proportion is an equation that shows two equivalent ratios.

Triangle Proportionality Theorem

The Triangle Proportionality Theorem states that if a line is parallel to one side of a triangle and it intersects the other two sides, then it divides those sides proportionally.

Triangle Proportionality Theorem Converse

The Triangle Proportionality Theorem converse states that if a line divides two sides of a triangle proportionally, then it is parallel to the third side.

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