You've been given a menu at a restaurant and you're trying to decide what to eat. You have a choice of 15 different entrees, 12 different side dishes and 4 different breads. How many possibilities do you have for lunch? Does it matter which order you choose them from the menu? In other words, when you order will it make any difference if you tell the waitress your bread order before your entree order?
Watch This
First watch this video to learn about combinations.
CK12 Foundation: Chapter2CombinationsA
Then watch this video to see some examples.
CK12 Foundation: Chapter2CombinationsB
Watch this video for more help.
Guidance
If you think about the lottery, you choose a group of lucky numbers in hopes of winning millions of dollars. When the numbers are drawn, the order in which they are drawn does not have to be the same order as on your lottery ticket. The numbers drawn simply have to be on your lottery ticket in order for you to win. You can imagine how many possible combinations of numbers exist, which is why your odds of winning are so small!
Combinations
are arrangements of objects
without
regard to order and without repetition, selected from a distinct number of objects. A combination of
\begin{align*}n\end{align*}
\begin{align*}{_n}C_r = \frac{n!}{r!(nr)!}\end{align*}
Example A
Evaluate:
\begin{align*}{_7}C_2\end{align*}
\begin{align*}{_7}C_2 &= \frac{7!}{2!(72)!}\\ {_7}C_2 &= \frac{7!}{2!(5)!}\\ {_7}C_2 &= \frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{(2 \times 1)(5 \times 4 \times 3 \times 2 \times 1)}\\ {_7}C_2 &= \frac{5,040}{(2)(120)}\\ {_7}C_2 &= \frac{5,040}{240}\\ {_7}C_2 &= 21\end{align*}
Example B
In how many ways can 3 desserts be chosen in any order from a menu of 10?
There are 10 menu items
\begin{align*}(n = 10)\end{align*}
\begin{align*}{_{10}}C_3 &= \frac{10!}{3!(103)!}\\ {_{10}}C_3 &= \frac{10!}{3!(7)!}\\ {_{10}}C_3 &= \frac{10 \times 9 \times 8}{3 \times 2 \times 1}\\ {_{10}}C_3 &= 120\end{align*}
Example C
There are 12 boys and 14 girls in Mrs. Cameron's math class. Find the number of ways Mrs. Cameron can select a team of 3 students from the class to work on a group project. The team must consist of 2 girls and 1 boy.
There are groups of both boys and girls to consider. From the 14 girls
\begin{align*}(n = 14)\end{align*}
\begin{align*}\text{Girls:}\\ {_{14}}C_2 &= \frac{14!}{2!(14 2)!}\\ {_{14}}C_2 &= \frac{14!}{2!(12)!}\\ {_{14}}C_2 &= \frac{87,178,291,200}{2(479,001,600)}\\ {_{14}}C_2 &= \frac{87,178,291,200}{958,003,200}\\ {_{14}}C_2 &= 91\end{align*}
From the 12 boys
\begin{align*}(n = 12)\end{align*}
\begin{align*}\text{Boys:}\\ {_{12}}C_1 &= \frac{12!}{1!(121)!}\\ {_{12}}C_1 &= \frac{12!}{1!(11)!}\\ {_{12}}C_1 &= \frac{479,001,600}{1(39,916,800)}\\ {_{12}}C_1 &= \frac{479,001,600}{39,916,800}\\ {_{12}}C_1 &= 12\end{align*}
Therefore, the number of ways Mrs. Cameron can select a team of 3 students (2 girls and 1 boy) from the class of 26 students to work on a group project is:
\begin{align*}\text{Total combinations} = {_{14}}C_2 \times {_{12}}C_1=91 \times 12=1,092\end{align*}
Points to Consider
 How does a permutation differ from a combination?
Guided Practice
There are 18 Democrats and 20 Republicans in a committee. Find the number of ways the committee can form a subcommittee consisting of 3 Democrats and 4 Republicans.
Answer:
There are groups of both Democrats and Republicans to consider. From the 18 Democrats
\begin{align*}(n = 18)\end{align*}
\begin{align*}\text{Democrats:}\\ {_{18}}C_3 &= \frac{18!}{3!(18 3)!}\\ {_{18}}C_3 &= \frac{18!}{3!(15)!}\\ {_{18}}C_3 &= \frac{18 \times 17 \times 16}{3 \times 2 \times 1}\\ {_{18}}C_3 &= \frac{4,896}{6}\\ {_{18}}C_3 &= 816\end{align*}
From the 20 Republicans
\begin{align*}(n = 20)\end{align*}
\begin{align*}\text{Republicans:}\\ {_{20}}C_4 &= \frac{20!}{4!(204)!}\\ {_{20}}C_4 &= \frac{20!}{4!(16)!}\\ {_{20}}C_4 &= \frac{20 \times 19 \times 18 \times 17}{4 \times 3 \times 2 \times 1}\\ {_{20}}C_4 &= \frac{116,280}{24}\\ {_{20}}C_4 &= 4,845\end{align*}
Therefore, the number of ways the committee can form a subcommittee consisting of 3 Democrats and 4 Republicans is:
\begin{align*}\text{Total combinations} = {_{18}}C_3 \times {_{20}}C_4=816 \times 4,845=3,953,520\end{align*}
Practice

Determine whether the following situations would require calculating a combination:
 Selecting 3 students to attend a conference in Washington, D.C.
 Selecting a lead and an understudy for a school play
 Assigning students to their seats on the first day of school
 In how many ways can you select 17 songs from a mix CD of a possible 38 songs?
 If an ice cream dessert can have 2 toppings, and there are 9 available, how many different selections can you make?
 If there are 17 randomly placed dots on a circle, how many lines can be formed using any 2 dots?
 A committee of 4 is to be formed from a group of 13 people. How many different committees can be formed?
 There are 4 kinds of meat and 10 veggies available to make wraps at the school cafeteria. How many possible wraps have 1 kind of meat and 3 veggies?

There are 15 freshmen and 30 seniors in the Senior Math Club. The club is to send 4 representatives to the State Math Championships.
 How many different ways are there to select a group of 4 students to attend the State Math Championships?
 If the members of the club decide to send 2 freshmen and 2 seniors, how many different groupings are possible?
 Julia is going on vacation, and she wants to pack 5 tshirts and 4 pairs of shorts in her suitcase. If Julia has 22 tshirts and 9 pairs of shorts from which to chose in her closet, in how many possible ways can she pack tshirts and shorts for her vacation?
 Of Major League Baseball's 16 National League teams and 14 American League teams, 4 teams from each league make the playoffs. How many possible groups of playoff teams are there in Major League Baseball?
 If Rick randomly chooses 3 months of the year to give up junk food, what is the probability that he gives up junk food during the first 3 months or the last 3 months of the year?