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# 2.10: Perimeter and Area

Created by: CK-12

## Triangles and Parallelograms

The Importance of Units – Students will give answers that do not include the proper units, unless it is required by the instructor. When stating an area, square units should be included, and when referring to a length, linear units should be used. Using proper units helps reinforce the basic concepts. With these first simple area problems including the units seems like a small detail, but as the students move to more complex situations combining length, area, and volume, units can be a helpful guide. In physics and chemistry dimensional analysis is an important tool.

The Power of Labeling – When doing an exercise where a figure needs to be broken into polynomials with known area formulas, it is important for the student to draw on and label the figure well. Each polygon, so far only parallelograms and triangles, should have their base and height labeled and the individual area should be in the center of each. By solving these exercises in a neat, orderly way student will avoid errors like using the wrong values in the formulas, overlapping polygons, or leaving out some of the total area.

Subtracting Areas – Another way of finding the area of a figure that is not a standard polygon is to calculate a larger known area and then subtracting off the areas of polygons that are not included in the target area. This can often result in fewer calculations than adding areas. Different minds work in different ways, and this method might appeal to some students. It is nice to give them as many options as possible so they feel they have the freedom to be creative.

The Height Must Be Perpendicular to the Base – Students will frequently take the numbers from a polygon and plug them into the area formula without really thinking about what the numbers represent. In geometry there will frequently be more steps. The students will have to use what they have learned to find the correct base and height and then use those numbers in an area formula. Remind students that they already know how to use a formula; many exercises in this class will require more conceptual work.

Write Out the Formula – When using an area formula, it is a good idea to have the students first write out the formula they are using, substitute numbers in the next step, and then solve the resulting equation. Writing the formula helps them memorize it and also reduces error when substituting and solving. It is especially important when the area is given and the student is solving for a length measurement in the polygon. Students will be able to do these calculations in their heads for parallelograms, and maybe triangles as well, but it is important to start good habits for the more complex polygons to come.

## Trapezoids, Rhombi, and Kites

It’s Arts and Crafts Time – Student have trouble remembering how to derive the area formulas. At this level it is required that they understand the nature of the formulas and why the formulas work so they can modify and apply them in less straightforward situations. An activity where student follow the explanation by illustrating it with shapes that they cut out and manipulate is much more powerful then just listening and taking notes. It will engage the students, keep their attention, and make them remember the lesson longer.

Trapezoid

1. Have student use the parallel lines on binder paper to draw a trapezoid. They should draw in the height and label it $h$. They should also label the two bases $b_1$ and $b_2$.
2. Now they can trace and cut out a second congruent trapezoid and label it as they did the first.
3. The two trapezoids can be arranged into a parallelogram and glued down to another piece of paper.
4. Identify the base and height of the parallelogram in terms of the trapezoid variables. Then substitute these expressions into the area formula of a parallelogram to derive the area formula for a trapezoid.
5. Remember that two congruent trapezoids were used in the parallelogram, and the formula should only find the area of one trapezoid.

Kite

1. Have the students draw a kite. They should start by making perpendicular diagonals, one of which is bisecting the other. Then they can connect the vertices to form a kite.
2. Now they can draw in the rectangle around the kite.
3. Identify the base and height of the parallelogram in terms of $d_1$ and $d_2$, and then substitute into the parallelogram area formula to derive the kite area formula.
4. Now have the students cut off the four triangles that are not part of the kite and arrange them over the congruent triangle in the kite to demonstrate that the area of the kite is half the area of the rectangle.

Rhombus

The area of a rhombus can be found using either the kite or parallelogram area formulas. Use this as an opportunity to review subsets and what they mean in terms of applying formulas and theorems.

## Areas of Similar Polygons

Adjust the Scale Factor - It is difficult for students to remember to square and cube the scale factor when writing proportions involving area and volume. Writing and solving a proportion is a skill they know well and have used frequently. Once the process is started, it is hard to remember to add that extra step of checking and adjusting the scale factor in the middle of the process. Here are some ways to reinforce this step in the students’ minds.

1. Inform students that this material is frequently used on the SAT and other standardized tests in some of the more difficult problems.
2. Play with graph paper. Have students draw similar shape on graph paper. They can estimate the area by counting squares, and then compare the ratio of the areas to the ratio of the side lengths. Creating the shapes on graph paper will give the students a good visual impression of the areas.
3. Write out steps, or have the students write out the process they will use to tackle these problems. (1) Write a ratio comparing the two polygons. (2) Identify the type of ratio: linear, area, or volume. (3) Adjust the ratio using powers or roots to get the desired ratio. (4) Write and solve a proportion.
4. Mix-up the exercises so that students will have to square the ratio in one problem and not in the next. Keep them on the lookout. Make them analyze the situation instead of falling into a habit.

1. The ratio of the lengths of the sides of two squares is $1:2$. What is the ratio of their areas?

Answer: $1: 4$

2. The area of a small triangle is $15 \;\mathrm{cm}^2$, and has a height of $5 \;\mathrm{cm}$. A larger similar triangle has an area of $60 \;\mathrm{cm}^2$. What is the corresponding height of the larger triangle?

area ratio $15:60$ or $1:4$ height linear ratio $1:2 = 10 \;\mathrm{cm}$

Height of larger triangle is twice the of the smaller triangle. $5 * 2$

3. The ratio of the lengths of two similar rectangles is $2:3$. The larger rectangle has a width of $18 \;\mathrm{cm}$. What is the width of the smaller rectangle?

$\frac{2}{3} & = \frac{x}{18} && \text{The\ width\ of\ the\ smaller\ rectangle\ is}\ 12\ \text{cm}. \\ x & = 12$

## Circumference and Arc Length

Pi is an Irrational Number – Many students can give the definition of an irrational number. They know that an irrational number has an infinite decimal that has no pattern, but they have not really internalized what this means. Infinity is a difficult concept. A fun way to help the students develop this concept is to have a pi contest. The students can chose to compete by memorizing digits of pi. They can be given points, possible extra credit, for ever ten digits or so, and the winner gets a pie of their choice. The students can also research records for memorizing digits of pi. The competition can be done on March $14^{\mathrm{th}}$, pi day. When the contest is introduced, there is always a student who asks “How many points do I get if I memorize it all?” It is a fun way to reinforce the concept of irrational numbers and generate a little excitement in math class.

How is Pi Calculated? - Students frequently ask how mathematicians calculate pi and how far they have gotten. One method is by approximating the circumference of a circle with inscribed or circumscribed polygons. Inspired students can try writing the code themselves, and possibly sharing it with the class. There are many other more commonly used methods, but they involve calculus or other mathematics that is beyond geometry students.

There Are Two Values That Describe an Arc – The measure of an arc describes how curved the arc is, and the length describes the size of the arc. Whenever possible, have the students give both values with units so that they will remember that there are two different numerical descriptions of an arc. Often student will give the measure of an arc when asked to calculate its length.

Arc Length Fractions – Fractions are a difficult concept for many students even when they have come as far as geometry. For many of them putting the arc measure over $360$ does not obviously give the part of the circumference included in the arc. It is best to start with easy fractions. Use a semi-circle and show how $180/360$ reduces to $\frac{1}{2}$, then a ninety degree arc, and then a $120 \;\mathrm{degree}$ arc. After some practice with fractions they can easily visualize, the students will be able to work with that eighty degree arc.

Exact or Approximate – When dealing with the circumference of a circle there are often two ways to express the answer. The students can give exact answers, such as $2 \pi$ cm or the decimal approximation $6.28 \;\mathrm{cm}$. Explain the strengths and weaknesses of both types of answers. It is hard to visualize $13 \pi \;\mathrm{feet}$, but that is the only way to accurately express the circumference of a circle with diameter $13 \;\mathrm{ft}$. The decimal approximations $41, 40.8, 40.84$, can be calculated to any degree of accuracy, are easy to understand in terms of length, but are always slightly wrong. Let the students know if they should give one, the other, or both forms of the answer.

## Circles and Sectors

Reinforce – This section on area of a circle and the area of a sector is analogous to the previous section about circumference of a circle and arc length. This gives students another chance to go back over the arguments and logic to better understand, remember, and apply them. Focus on the same key points and methods in this section, and compare it to the previous section. Mix-up exercises so students will see the similarities and learn each more thoroughly.

Don’t Forget the Units – Remind students that when they calculate an area the units are squared. When an answer contains the pi symbol, students are more likely to leave off the units. In the answer $7 \pi \;\mathrm{cm}^2$, the $\pi$ is part of the number and the $\mathrm{cm}^2$ are units of area.

Draw a Picture – When applying geometry to the world around us, it is helpful to draw, label, and work with a picture. Visually organize information is a powerful tool. Remind students to take the time for this step when calculating the areas of the irregular shapes that surround us.

1. What is the area between two concentric circles with radii $5 \;\mathrm{cm}$ and $12 \;\mathrm{cm}$?

Answer: $144\pi - 25\pi = 119\pi \;\mathrm{cm}^2$

2. The area of a sector of a circle with radius $6 \;\mathrm{m}$, is $12\pi \;\mathrm{cm}^2$. What is the measure of the central angle that defines the sector?

$12\pi & = \frac{x}{360} * \pi * 6^2 && \text{The central angle measures}\ 120\ \text{degrees}. \\x & = 120$

3. A square with side length $5\sqrt{2} \;\mathrm{cm}$ is inscribed in a circle. What is the area of the region between the square and the circle?

Answer: $\pi * 5^2 - (5\sqrt{2})^2 = 25\pi - 50 \approx 28.5 \;\mathrm{cm}^2$

## Regular Polygons

The Regular Hypothesis – Make it clear to students that these formulas only work for regular polygons, that is, polygons will all congruent sides and angles. The regular restriction is part of the hypothesis. Many times the hypotheses of important theorems in mathematics are quite restrictive, but that does not necessarily limit the value of the theorem. If a polygon is approximately regular, then the formula can be used to get an approximate area. Also, the method of breaking the polygon into triangles can be applied to non-regular polygons, but each triangle may be different and therefore each area computed separately. It is important to understand how the theorem or formula was derived so it can be adapted to other situations. Knowing this will motivate students to work to understand the formulas.

Numerous Variables and Relationships – Polygons come with an entire new set of variable. Students need to learn what these knew variable represent, how they are related to the triangles that makeup the polygon, and how they are related to each other. This will take some time and practice. If students do not have time to memorize what the variables represent, they will not understand how they are being put together in the various formulas. Find convenient breaking points and give students time, examples, or activities to help them become familiar with the material. If it all comes too fast, student will get lost and frustrated.

What is $n$? - Students will frequently be given the value of $n$, but will not realize it because it is not given in the form they are expecting. An exercise may state, “Each side of a regular hexagon is nine inches long.” The students will see the nine and assign it to the variable $s$, but not notice that they are also being given the value of $n$; a hexagon has six sides.

Let the Radius be One – The simplification of only considering polygons inscribed in a unit circle by letting the radius be equal to one, may seem a bit odd to students. Let them know that this is being done in preparation for more advanced trigonometry. In trigonometry ratios of side lengths of similar triangles are considered, and the size of the triangles in not important. Letting them know that this simplification becomes useful in the future will reassure them that the course of their mathematics education is well designed.

1. The area of a regular hexagon is $24\sqrt{3} \;\mathrm{cm}^2$. What is the length of each side?

$24\sqrt{3} & = \frac{1}{2} * s * \frac{1}{2} s \sqrt{3}*6 && \text{Each\ side\ has\ a\ length\ of}\ 4\ \text{cm}. \\s & = 4$

## Geometric Probability

Count Carefully – Counting is the most challenging aspect of probability for students. It is easy to make an error when thinking of all the possible outcomes and determining how many of them are favorable. The best way to guard against errors is to make logical, orderly lists. The goal is for the students to see a pattern so that eventually they will be able to get the count without listing all of the possibilities.

Outcome Favorable? Outcome Favorable?
$(N_1,N_2)$ No $(D,N_1)$ No
$(N_1,D)$ No $(D,N_2)$ No
$(N_1,Q)$ Yes $(D,Q)$ Yes
$(N_2,N_1)$ No $(Q,N_1)$ Yes
$(N_2,D)$ No $(Q,N_2)$ Yes
$(N_2,Q)$ Yes $(Q,D)$ Yes

Does Order Matter? – One of the hardest decisions for a new probability student to make when analyzing a situation is to determine if different permutations should be counted separately or not. Take Example Two from this section. Is there a first coin and a second coin? Does it matter if Charmane sees the quarter of the dime first? In this case, it does not because the two coins are taken at the same time. To compare have the students consider the situation where first one coin is drawn and then a second. In this case there are more possible outcomes. The probability remains the same, $50\%$, but now it is calculated as $\frac{6}{12}$ instead of $\frac{3}{6}$. It is not always the case that considering order results in the same probability as when order is not considered. Note that this example can be reduced to the simpler question of whether a quarter is one of the two coins drawn.

1. A man throws a dart at a circular target with radius $6 \;\mathrm{inches}$. He is equally likely to hit anywhere in the target. What is the probability that he is within $2\;\mathrm{inches}$ of the center of the target?

$\frac{\pi 2^2}{\pi 6^2}=\frac{1}{9} \approx .11 && \text{There is an approximately}\ 11\% \ \text{chance that he will hit within}\ 2 \ \text{inches of the target.}$

2. There is a $110 \;\mathrm{mile}$ stretch of road between the centers of two cities. A hospital is located 30 miles from the center of one city. If an accident is equally likely to occur anywhere between the two cities, what is the probability it is within ten miles of the hospital?

$\frac{20}{110} \approx .18 && \text{There is an approximately}\ 18\% \ \text{chance that the accident will be within}\ 10 \ \text{miles of the hospital.}$

## Date Created:

Feb 22, 2012

Feb 23, 2012
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