You are given a list of Trig Identities. One of those identities is . Prove this identity without graphing.
Trigonometric identities are true for any value of (as long as the value is in the domain). In the Reciprocal Trigonometric Functions concept from the previous chapter, you learned about secant, cosecant, and cotangent, which are all reciprocal functions of sine, cosine and tangent. These functions can be rewritten as the Reciprocal Identities because they are always true.
Other identities involve the tangent, variations on the Pythagorean Theorem, phase shifts, and negative angles. We will discover them in this concept.
. Show that .This is the Tangent Identity .
Solution: Whenever we are trying to verify, or prove, an identity, we start with the statement we are trying to prove and work towards the desired answer. In this case, we will start with and show that it is equivalent to . First, rewrite sine and cosine in terms of the ratios of the sides.
Then, rewrite the complex fraction as a division problem and simplify.
We now have what we wanted to prove and we are done. Once you verify an identity, you may use it to verify other identities.
Show that is a true identity.
Solution: Change the sine and cosine in the equation into the ratios. In this example, we will use as the opposite side, is the adjacent side, and is the hypotenuse (or radius), as in the unit circle.
Now, from the Pythagorean Theorem. Substitute this in for the numerator of the fraction.
This is one of the Pythagorean Identities and very useful.
Verify that by using the graphs of the functions.
Solution: The function is a phase shift of of the sine curve.
The red function above is and the blue is . If we were to shift the sine curve , it would overlap perfectly with the cosine curve, thus proving this Cofunction Identity .
Concept Problem Revisit First, recall that , where is the endpoint of the terminal side of on the unit circle.
Now, if we have , what is its endpoint? Well, the negative sign tells us that the angle is rotated in a clockwise direction, rather than the usual counter-clockwise. If we make this rotation, we see that as well, as illustrated in the following diagram.
We know that , so we can set the two expressions equal to one another.
We can now flip this identity around to get:
1. Prove the Pythagorean Identity:
2. Without graphing, show that .
1. First, let’s use the Tangent Identity and the Reciprocal Identity to change tangent and secant in terms of sine and cosine.
Now, change the 1 into a fraction with a base of and simplify.
In the second to last step, we arrived at the original Pythagorean Identity in the numerator of the left-hand side. Therefore, we can substitute in 1 for this and the two sides of the equation are the same.
2. First, recall that , where is the endpoint of the terminal side of on the unit circle.
Now, if we have , what is it’s endpoint? Well, the negative sign tells us that the angle is rotated in a clockwise direction, rather than the usual counter-clockwise. By looking at the picture, we see that . Therefore, if , then and combining the equations, we have .
- Show that by following the steps from Example A.
- Show that . Refer to Example A to help you.
- Show that by following the steps from #1 in the Guided Practice.
- Explain why by using the graphs of the two functions.
- Following the steps from #2 in the Guided Practice, show that .
- Explain why is true, using the Tangent Identity and the other Negative Angle Identities.
Verify the following identities.
Show that is true for the following values of .
- Recall that a function is odd if and even if . Which of the six trigonometric functions are odd? Which are even?