You are working on a project in your Industrial Arts class. You have been instructed to design a building. You have a plastic triangular piece that helps you with straight edges and designs. This triangle has interior angles of \begin{align*}30^\circ\end{align*}

You trace out the bottom and left edge of the triangle on the paper to serve as the side and bottom of the structure. Looking at the length of the base of the building, you see that it is 7 inches long. Can you determine what the height of the building is from this information?

Read on, and at the conclusion of this Concept you'll be able to do just that.

### Watch This

James Sousa Examples: Solve a 30-60 Right Triangle

### Guidance

\begin{align*}30-60-90\end{align*}

Recall from geometry that an altitude, \begin{align*}h\end{align*}

\begin{align*}s^2 + h^2 & = (2s)^2\\ s^2 + h^2 & = 4s^2\\ h^2 & = 3s^2\\ h & = s\sqrt{3}\end{align*}

From this we can conclude that the length of the longer leg is the length of the short leg multiplied by \begin{align*}\sqrt{3}\end{align*}

Notice, that the shortest side is *always* opposite the smallest angle and the longest side is *always* opposite \begin{align*}90^\circ\end{align*}

#### Example A

Find the lengths of the two missing sides in the \begin{align*}30-60-90\end{align*}

**Solution:** Determine which side in the \begin{align*}30-60-90\end{align*}

\begin{align*}4\sqrt{3}\end{align*}

#### Example B

Find the lengths of the two missing sides in the \begin{align*}30-60-90\end{align*}

**Solution:** Determine which side in the \begin{align*}30-60-90\end{align*}

17 is the hypotenuse because it is opposite the right angle. In the \begin{align*}x:x\sqrt{3}:2x\end{align*}

#### Example C

Find the lengths of the two missing sides in the \begin{align*}30-60-90\end{align*}

**Solution:** Determine which side in the \begin{align*}30-60-90\end{align*}

15 is the long leg because it is opposite the \begin{align*}60^\circ\end{align*}

\begin{align*}x\sqrt{3} & = 15\\ x & = \frac{15}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{15\sqrt{3}}{3} = 5\sqrt{3} \quad \text{So, the short leg is} \ 5\sqrt{3}.\end{align*}

Multiplying \begin{align*}5\sqrt{3}\end{align*}

### Guided Practice

1. Find the lengths of the two missing sides in the \begin{align*}30-60-90\end{align*} triangle.

2. Find the lengths of the two missing sides in the 30-60-90 triangle below.

3. Find the angles in the \begin{align*}30-60-90\end{align*} triangle.

**Solutions:**

1. Since the given side has a length of 8 and is the side which is opposite the right angle, we know that this is the "2x" side of the triangle. Therefore, the short side of the triangle is \begin{align*}\frac{8}{2} = 4\end{align*} and the third side of the triangle is \begin{align*}4 \sqrt{3}\end{align*}.

2. We can see that the shortest side of the triangle has a length of 3 while the longest side has a length of 6 and the other side has a length of \begin{align*}3 \sqrt{3}\end{align*}. This means that the \begin{align*}30^\circ\end{align*} angle is opposite the side with length \begin{align*}3\end{align*}, the \begin{align*}60^\circ\end{align*} angle is opposite the side with length \begin{align*}3 \sqrt{3}\end{align*}, and the \begin{align*}90^\circ\end{align*} angle is opposite the side with length \begin{align*}6\end{align*}.

3. The length of the given side is \begin{align*}3\sqrt{3}\end{align*}, and is opposite the \begin{align*}60^\circ\end{align*} angle. This means that the side opposite the \begin{align*}30^\circ\end{align*} angle is \begin{align*}3\end{align*}, and the length of the side opposite the \begin{align*}90^\circ\end{align*} angle is \begin{align*}6\end{align*}

### Concept Problem Solution

Since you know the ratios of sides of a 30-60-90 triangle, you know that since the bottom side has a length of \begin{align*}7\end{align*} cm, the left side must have a length of \begin{align*}7\sqrt{3} \approx 12.12\end{align*} cm.

### Explore More

- In a 30-60-90 triangle, if the shorter leg is 8, then the longer leg is __________ and the hypotenuse is ___________.
- In a 30-60-90 triangle, if the shorter leg is 12, then the longer leg is __________ and the hypotenuse is ___________.
- In a 30-60-90 triangle, if the longer leg is 10, then the shorter leg is __________ and the hypotenuse is ___________.
- In a 30-60-90 triangle, if the shorter leg is 16, then the longer leg is __________ and the hypotenuse is ___________.
- In a 30-60-90 triangle, if the longer leg is 3, then the shorter leg is __________ and the hypotenuse is ___________.
- In a 30-60-90 triangle, if the shorter leg is \begin{align*}x\end{align*}, then the longer leg is __________ and the hypotenuse is ___________.
- In a 30-60-90 triangle, if the longer leg is \begin{align*}x\end{align*}, then the shorter leg is __________ and the hypotenuse is ___________.
- A rectangle has sides of length 7 and \begin{align*}7 \sqrt{3}\end{align*}. What is the length of the diagonal?
- Two (opposite) sides of a rectangle are 15 and the diagonal is 30. What is the length of the other two sides?
- What is the height of an equilateral triangle with sides of length 6 in?
- What is the area of an equilateral triangle with sides of length 10 ft?
- A regular hexagon has sides of length 3 in. What is the area of the hexagon?
- The area of an equilateral triangle is \begin{align*}36 \sqrt{3}\end{align*}. What is the length of a side?
- If a road has a grade of \begin{align*}30^\circ\end{align*}, this means that its angle of elevation is \begin{align*}30^\circ\end{align*}. If you travel 3 miles on this road, how much elevation have you gained in feet (5280 ft = 1 mile)?
- If a road has a grade of \begin{align*}30^\circ\end{align*}, this means that its angle of elevation is \begin{align*}30^\circ\end{align*}. If you travel x miles on this road, how much elevation have you gained in feet (5280 ft = 1 mile)?