Q: What volume of oxygen is required to completely combust 0.650 L of propane (C3H8) at step?

Flexi Says: The equation for the combustion of propane gas produces carbon dioxide and water vapor is:

C₃H₈ (g)+ 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)

From the equation, we can tell that 1 unit volume of propane requires 5 unit volumes of O₂ for combustion. For any given volume 'x' of propane, the volume of O₂ required to complete the combustion reaction will be 5x.